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Этот код нужно в тему готовых решений. С головы его не выдумать быстро, рабочий вариант.

igrik, просто супер! Работает идеально.

По ходу дела возник еще один вопрос. Эра позволяет блокировать регенерацию существ, но вот элексир продолжает работать. Как его можно отключить?

igrik, awesome!

I wonder if customising Necromancy is still a thing? I wish the code can help someone if it has not yet been revealed.

GitHub

Edit: Fixed a typo thanks to daemon_n

Archer30,
!!FU|(side)=-1/i^battle_hero_%(side)^=(NO_HERO):E

Looking for help with a function for getting a random position for summoning with BU:S

Input: Side for summoning, is Double Wide (monster Flag)
Output: random available position for BU:S summoning (both hex must not be unoccupied if doubled wide)

It looks like I have achieved undesirable outcome with it...I would like to know what could possibly be wrong.
I understand that the code must be optimised a lot more

Seems like code is valid.

But I would generate single array of valid positions first and then generate single random value in 0..array_size - 1 range. Value under generated index will be the result.
---------------------------------
Another variant is to fill "positions" array of 186 items with 0..185 values correspondingly.
Also define variable numCandidates = 186 (array size).

Repeat until free position is found or numCandidates = 0.
Generate random value in 0..numCandidates - 1 range.

Battle pos = positions[generated random index]
If position is not free or invalid, then

positions[generated random index] = numCandidates - 1; we make array index to actually point to another position, thus virtually removing tested hex from further check attempts
numCandidates = numCandidates - 1; decrease positions array size, because the last position is not referrered by "generated random index".

------------------------

For instance, imagine there are max 8 positions on battle: 0..7.

Define positions array = (0, 1, 2, 3, 4, 5, 6, 7).
numCandidates = 8

generated random value 0..(8 - 1) = 3
Look at positions array at index 3. positions[3] = 3.
Check battle hex #3, it's occupied.

positions[3] = numCandidates - 1 = 7
numCandidates = numCandidates - 1 = 7
Thus we have updated positions array: (0, 1, 2, 7, 4, 5, 6)

As you see, new array does not have hex #3 anymore.

Both approaches guarantee to find free positions. Your variant with 100 generations may fail for unlucky generated sequences.

Berserker, great approaches! Well, I had a hard time using the function I wrote. For some reason, I can't get the second IF:M shown on my screen from time to time. This is so weird as there is no FU:E in the function, it is technically not possible...

At the moment I need some advice on writing. Is there a convenient way to bypass invalid positions (0, 17, 34, those hex out of the battlefield)? Both BU:E/BU:D returns -1, making it not possible to
distinguish them with empty hex.

Alternatively, is there a way to remove mutual elements from both arrays? You know what I am thinking about

(14.03.2022 19:58)Archer30 Wrote: [ -> ]Is there a convenient way to filter invalid positions (0, 17, 34, those hex out of the battlefield)?

I think something like this:

Archer30, here is the complete function. It has not yet been fully tested, but at first glance it works.

wessonsm, thanks. I forgot that it can be solved by math lol.

Umm. Usually, I would use &(variable) for booleans. My (isDoubleWide) and (isAvailPos) are either 0 or 1. I believe we were introduced &(variable) some versions around ERA 3.5, it equals to &(variable)>(FALSE). Is that a bad practice though?

Quote:Umm. Usually, I would use &(variable) for booleans. My (isDoubleWide) and (isAvailPos) are either 0 or 1. I believe we were introduced &(variable) some versions around ERA 3.5, it equals to &(variable)>(FALSE). Is that a bad practice though?

No, it's a good practice. wessonsm just was not aware of this improvement.

P.S. Чуток дооформил код выше.

Archer30, Berserker. I really missed this moment in the changelog, apparently I didn’t read well.
Sorry for the misinformation and thanks for the clarification.
I'll edit my post to avoid misleading others.

wessonsm, no need to worry about it

Well, I come up with another question with BU:S summoning, I want to write a function with the following requirements, and I'd like to know the best approach to it.

The task of the function: Find a random but closest position to the given position for BU:S summoning. The monster for summoning is known for whether it is double wide, and the side for summoning.
Input: a known Position, Is Double Wide, Side.
Output: Closest position to the known position for BU:S


I have two approaches in mind, first one:
- loop through all the hex on the battlefield
- Check the distance between the looped hex and the known hex
- Collect the hex with the smallest distance and put to the array
- Get a random position from this array

Second one:
- Check for the closet positions around the given position. The first batch would be the six hex around the target
- If none is available, check for a larger hex around the target, repeat this if nothing is found again

Basically, the first approach is easier to code, but I am worried about its efficiency. The second approach should be faster, but it is a bit tricky to code. If I can't combine the steps, I might end up checking for every single position manually.

Any thoughts?

Archer30,
It seems that the first method will be quite effective if we have a simple and fast function for calculating the distance between two hexes.
The second way can be implemented if you come up with a fairly simple algorithm for bypassing hexes along a spiral path.
I think this can be done by converting the hex numbers to pairs of coordinates (row, column).
The second way seems more interesting to me, and I will think about it.

We already had distance calculating function (based on row and column) on this forum in ERM 1, probably. I have old code in Pascal.

BATTLEFIELD_LINE_SIZE = 17;